# frequency of oscillation in a twin t oscillator

Discussion in 'Electronics Homework Help' started by bazzel, Nov 17, 2012.

1. ### bazzel

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Hello all.I have a math question that hopefully someone can answer

I got so far in working out the frequency of a twin t but got stuck at this point

1/6.28 square root of 1/225x 0.0000000010

it should work out as 1059.9 Hz but i cant figure out how to get there, any thoughts?

bazzel, Nov 17, 2012

2. ### duke37VIP Member

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I might be able to do this if you add brackets such as

1/(SQRT(1/225) * 1e-9)

You should have an even number of brackets.

duke37, Nov 17, 2012

3. ### duke37VIP Member

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According to my book, the frequency of the twin T notch is

F=1/(2*pi*R*C)

Where is the square root?

duke37, Nov 17, 2012
4. ### bazzel

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Ive attatched a scanned copy of the formula if thats any help.
What Im struggling with is getting to the bottom answer in brackets (6666) from the sum above it (square rooot of 1/225 x 10minus 10)

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bazzel, Nov 20, 2012
5. ### duke37VIP Member

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This should have been answered by an Australian, they are upside down!

So it is an asymetrical circuit with different resistances so you get SQRT(R1*R2)

F = 1/(2*pi)*SQRT(1/(R1*R2*C1*C2))

R1=15k
R2=1.5k
C1=100n = 1E-7
C2=10n = 1E-8

using the notation that E is 10 to the power of
Take the inner brackets
A= R1*R2*C1*C2 = 2.25E-6
1/A = 444444
SQRT (1/A) = 6666.7
F=6666.7/(2*pi) = 1061

Near enough?

duke37, Nov 20, 2012

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