frequency of oscillation in a twin t oscillator

Discussion in 'Electronics Homework Help' started by bazzel, Nov 17, 2012.

  1. bazzel

    bazzel

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    Hello all.I have a math question that hopefully someone can answer

    I got so far in working out the frequency of a twin t but got stuck at this point

    1/6.28 square root of 1/225x 0.0000000010

    it should work out as 1059.9 Hz but i cant figure out how to get there, any thoughts?
    bazzel, Nov 17, 2012
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  2. bazzel

    duke37 VIP Member

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    I might be able to do this if you add brackets such as

    1/(SQRT(1/225) * 1e-9)

    You should have an even number of brackets.
    duke37, Nov 17, 2012
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  3. bazzel

    duke37 VIP Member

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    According to my book, the frequency of the twin T notch is

    F=1/(2*pi*R*C)

    Where is the square root?
    duke37, Nov 17, 2012
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  4. bazzel

    bazzel

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    Ive attatched a scanned copy of the formula if thats any help.
    What Im struggling with is getting to the bottom answer in brackets (6666) from the sum above it (square rooot of 1/225 x 10minus 10)
    Cheers in advance

    Attached Files:

    bazzel, Nov 20, 2012
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  5. bazzel

    duke37 VIP Member

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    This should have been answered by an Australian, they are upside down!

    So it is an asymetrical circuit with different resistances so you get SQRT(R1*R2)

    F = 1/(2*pi)*SQRT(1/(R1*R2*C1*C2))

    R1=15k
    R2=1.5k
    C1=100n = 1E-7
    C2=10n = 1E-8

    using the notation that E is 10 to the power of
    Take the inner brackets
    A= R1*R2*C1*C2 = 2.25E-6
    1/A = 444444
    SQRT (1/A) = 6666.7
    F=6666.7/(2*pi) = 1061

    Near enough?
    duke37, Nov 20, 2012
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  6. bazzel

    bazzel

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    Cheers duke. Thats great,thanks for taking the time
    bazzel, Nov 20, 2012
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